f(x) = e^2x+e^-x
over the specified interval 0 <= x <= ln 2
The answer is supposed to work out to be 3 I believe, but I keep getting really weird answers. Thanks!
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Calculus help! Find the avg. value of the function e^2x+e^-x over interval 0<x<ln 2?
April 30th, 2008 · 2 Comments
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2 responses so far ↓
1 Matt // Apr 30, 2008
take the integral:
(.5)(e^2x) - e^-x
evaluate from 0 to ln2:
[(.5)(4) - (.5)] - [(.5)(1) - 1] = 2
ummm, are you sure its not 2?
2 M C // Apr 30, 2008
1/ln2 * (integral of e^2x+e^-x from 0 to ln2) = 2/ln2
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