Scores on a training test are normally distributed with a mean of 73 and a standard deviation of 8. For a sample of size 36, what is the standard error?
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Scores on a training test are normally distributed with a mean of 73 and a standard deviation of 8. For a sample of size 36, what is the standard error?
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1 response so far ↓
1 nooney5 // Jun 30, 2008
SE = stdev/sqrt(sample size)
SE = 8/sqrt(36) = 8/6=4/3
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