It’s been a loong summer and I’ve forgotten a lot of math. Please guide me through this problem?
The V in liters of air during a 5 sec respiratory cycle is shown by V=0.1729 t+ 0.1522t^2 - 0.0374t^3 where t is seconds. What is the avg volume of air in one cycle?
So i started by integrating the V from 0 to 5, the cycle.
(1/5) [(0.1729t^2/2) +(0.1522t^3/3) - (0.0374t^4/4)- 0]
=(1/5)63424.6718
=12684.93436
hopefully this is right, but that is very unlikely… please explain to me how to do this if I have it wrong. Thanks a bunch!
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1 response so far ↓
1 robert+elzinga // Sep 13, 2008
It looks like you did it correctly.
1/(b-a) Integral from a to b of V(t)
will give the average volume
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